v^2+4v=12

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Solution for v^2+4v=12 equation:


Simplifying
v2 + 4v = 12

Reorder the terms:
4v + v2 = 12

Solving
4v + v2 = 12

Solving for variable 'v'.

Reorder the terms:
-12 + 4v + v2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 4v + v2 = 0

Factor a trinomial.
(-6 + -1v)(2 + -1v) = 0

Subproblem 1

Set the factor '(-6 + -1v)' equal to zero and attempt to solve: Simplifying -6 + -1v = 0 Solving -6 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1v = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1v = 0 + 6 -1v = 0 + 6 Combine like terms: 0 + 6 = 6 -1v = 6 Divide each side by '-1'. v = -6 Simplifying v = -6

Subproblem 2

Set the factor '(2 + -1v)' equal to zero and attempt to solve: Simplifying 2 + -1v = 0 Solving 2 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1v = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1v = 0 + -2 -1v = 0 + -2 Combine like terms: 0 + -2 = -2 -1v = -2 Divide each side by '-1'. v = 2 Simplifying v = 2

Solution

v = {-6, 2}

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